Question

x^2+2xy-z^2-2yz factorise

Answer 1

Answer:

${x}^{2} + 2xy - {z}^{2} - 2yz$

$x(x + 2y) - z(z + 2y)$

$( x - z)(x +z+ 2y)$

here is your answer

hope it helps you..!!!

Answer 2

Answer:

(x-z)(x+z+2y)

Step-by-step explanation:

Factorization:

x^2-z^2+2xy-2yz

(Formula:a^2-b^2=(a-b)(a+b))

(x-z)(x+z)+2y(x-z)

(x-z)(x+z+2y)