Question

x^2+2y^2=3xy, where x not equal to y and x,y not equal to 0 then x:y=?​

Answer 1

Answer:

(xy)2+3(xy)−18=0(xy)2+3(xy)−18=0 --> solving for xyxy -->  xy=−6xy=−6  (not a valid solution: xyxy must be positive as both unknowns are positive) or xy=3xy=3 --> so xy=3xy=3 --> x=3yx=3y --> x2=9y2x2=9y2.

Step-by-step explanation: