x/2+ 2y/3=-1 &x/1 -y/3= 3
(hint Take LCM and simplify
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=> x/2+2y/3= -1
=> 3x/6+4y/6= -1
=> 3x+4y/6 = -1
=> 3x+4y = -6 -----(1)
=> x/1-y/3=3
=> 3x-y/3 = 3
=> 3x-y = 9
=> 3x-9=y -------(2)
SUBSTITUTING (2) IN (1)
=> 3x + 4(3x-9) = -6
=> 3x + 12x - 36 = -6
=> 15x = -6+36
=> 15x = 30
=> x = 2
=> y = 3(2)-9
= 6-9 = -3
therefore, x = 2 and y = -3
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