Question

x/2+2y/3=-1 and x/3-y/2=13/6 solve equal.

Answer 1

Here is your answer-

Answer 2

According to the question

$\frac{x}{2}+\frac{2y}{3}=-1$  $\frac{x}{3}+\frac{y}{2}=\frac{13}{6}$

$\frac{3x+4y}{6}=-6$   $\frac{2x-3y}{6}=\frac{13}{6}$

$3x+4y=-36$ ......(1)

$2x-3y=13$ ......(2)

Solve both equations

$3x+4y=-36\times 3$

$2x-3y=13\times 4$

$9x+12y=108$

$8x-12y=52$

$17x=160$

$x=9.41$

put $x$ value in equation (1)

$9\times 9.41+12y=108$

$84.69+12y= 108$

$12y=23.31$

$y=1.9425$