X/2+2y/3=-1 and. X-y/2=3 solve
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by equating the equations
3x+2y=-6---(I)
2x-y=6----(ii)
multiply the (I) by negative 1
we get
-3x-2y=6----(iii)
from (ii) and (iii)
-3x-2y=2x-y
-2y+y=5x
-y=5x
y=-5x
now substitute y in (ii)
2x-5x=6
-3x=6
x=-2
y=-5(-2)
=10
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