Question

x/2+2y/3=-1 ; x-y/3=3 solve by elimination method. pls very aurjent pls.....................

Answer 1

Heya,

By elimination method,

x/2 + 2y /3 = - 1 ………..(1)

x – y/3 = 3 ………..(2)

Multiplying equation (1) by 2, we obtain

x + 4y/3 = - 2 ………(3) and,

x – y/3 = 3 ………..(2)

Subtracting equation (2) from equation (3), we obtain

5y /3 = -5

Divide by 5 and multiply by 3 we get,

Y = -15/5 Y = - 3

Substituting in equation (2), we obtain

x – y/3 = 3 ………..(2)

x – (-3)/3 = 3

=> x + 1 = 3 x

=>x= 2

Hence, x = 2 and y = −3

HOPE IT HELPS:-))

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Answer 2

Answer:

x = 2 and y = −3

Step-by-step explanation:Heya,

By elimination method,

x/2 + 2y /3 = - 1 ………..(1)

x – y/3 = 3 ………..(2)

Multiplying equation (1) by 2, we obtain

x + 4y/3 = - 2 ………(3) and,

x – y/3 = 3 ………..(2)

Subtracting equation (2) from equation (3), we obtain

5y /3 = -5

Divide by 5 and multiply by 3 we get,

Y = -15/5 Y = - 3

Substituting in equation (2), we obtain

x – y/3 = 3 ………..(2)

x – (-3)/3 = 3

=> x + 1 = 3 x

=>x= 2

Hence, x = 2 and y = −3

HOPE IT HELPS:-))

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