x/2+2y/3=1 x-y/3=3 using substitution method
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Answer:
Step-by-step explanation:
To solve the following equation:
x/2 + 2y/3= 1 .... (1)
x- y/3= 3 .... (2)
Multiply both the first equations by 6 and the second by 3, we get
3x + 4y = 6 .... (3)
3x - y = 9 .... (4)
Subtracting equation (4) from (3), we get
5y = -15 => y = 3
Put y = -3 in equation (4),
3x - (3) =9
=> 3x + 3 = 9
=> 3x = 6
=> x = 2.
Hence x =2 and y = 3.
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