x/2+2y/3=-1and x-y/3=3
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x/2+2y/3=-1 and x-y/3=3
:- x/2+2y/3=-1 -(1)
x-y/3=3 -(2)
From (1), we get :-
(3x+4y)/6 =-1
3x+4y=-6 -(3)
From (2), we get :-
(3x-y)/3=3
3x-y=9 -(4)
Subtract (4) from (3)
3x+4y=-6
3x - y = 9
- + -
——————
0 +5y=-15
——————
5y=-15
[y=-3]
Use value of y in (1)
x/2+{2×(-3)}/3=-1
x/2-6/3=-1
x/2-2=-1
x/2=-1+2
x/2=1
x=1×2
[x=2]
Hence, solution is x=2 and y=-3.
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