(x/2+2y)(x^2/4-xy+4y^2)
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Answer:
x^3/8+8y^3
Step-by-step explanation:
(x/2+2y)(x^2/4-xy+4y^2) {(a+b)(a^2-ab+b^2)=a^3+b^3}
a=x/2
b=2y
(x/2+2y)(x^2/4-xy+4y^2)
=(x/2)^3+(2y)^3
=
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