x^2- (√3+1)x + √3 = 0 find x
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x^2 - √3x - x + √3 = 0
x ( x- √3) - ( x- √3) = 0
( x- √3) (x-1) = 0
( x- √3) = 0 or (x-1)=0
x= √3 or x= 1
Please mark my answer as brainliest
x ( x- √3) - ( x- √3) = 0
( x- √3) (x-1) = 0
( x- √3) = 0 or (x-1)=0
x= √3 or x= 1
Please mark my answer as brainliest
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