Question

x/2 + 3/2 = 2x/5 - 1


Please help solve this question

Answer 1

Answer:

-25

Step-by-step explanation:

x/2 + 3/2 = 2x/5 - 1

= 2x/5 - x/2 = 3/2 + 1

= (4x - 5x)/10 = (3 + 2)/2

= 1x/10 = 5/2

= 1x × 2 = 10 × 5

= 2x = 50

= x = 50/-2

= 25/-1

= -25

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Answer 2

Question

Find the value of 'x' in the equation ⇒ $\frac{x}{2} +\frac{3}{2} = \frac{2x}{5} -1$

$\rule{300}{1}$

Answer

Let's solve your equation step-by-step

$\frac{x}{2} +\frac{3}{2} = \frac{2x}{5} -1$

Step 1: Simplify both sides of the equation.

⇒ $\frac{x}{2} +\frac{3}{2} = \frac{2x}{5} -1$

⇒ $\frac{1}{2}x +\frac{3}{2} = \frac{2}{5}x +-1$

⇒ $\frac{1}{2}x +\frac{3}{2} = \frac{2}{5}x -1$

Step 2: Subtract $\frac{2}{5}x$ from both sides.

⇒ $\frac{1}{2}x +\frac{3}{2} -\frac{2}{5}x= \frac{2}{5}x -1-\frac{2}{5}x$

⇒ $\frac{1}{10}x+\frac{3}{2}=-1$

Step 3: Subtract $\frac{3}{2}$ from both sides.

⇒ $\frac{1}{10}x+\frac{3}{2}-\frac{3}{2}=-1-\frac{3}{2}$

⇒ $\frac{1}{10}x=\frac{-5}{2}$

Step 4: Multiply both sides by 10.

⇒ $10\times \frac{1}{10}x=10 \times \frac{-5}{2}$

⇒ $x= -25$

Verification if x = -25

⇒ $\frac{x}{2} +\frac{3}{2} = \frac{2x}{5} -1$

⇒ $\frac{-25}{2} +\frac{3}{2} = \frac{2\times -25 }{5} -1$

⇒ $\frac{-22}{2} = \frac{-50 }{5} -1$

⇒ $-11 = -10 -1$

⇒ $-11=-11$

∴ LHS = RHS

∴ x = -25 in the given equation.

$\rule{300}{1}$