Question

X^2-(√3+2)X+2√3=0
tell me the answer​

Answer 1

${x}^{2} - \sqrt{3} x + 2x + 2 \sqrt{3 } = 0$

$x(x - \sqrt{3} ) - 2(x - \sqrt{3} ) = 0$

$(x - \sqrt{3} )(x - 2) = 0$

$either \: x - \sqrt{3} = 0$

$x = \sqrt{3}$

$or \: \:x - 2 = 0$

$x = 2$

Answer 2

Answer:

$x2−3x+2x+23=0</p><p></p><p>x(x - \sqrt{3} ) - 2(x - \sqrt{3} ) = 0x(x−3)−2(x−3)=0</p><p></p><p>(x - \sqrt{3} )(x - 2) = 0(x−3)(x−2)=0</p><p></p><p>either \: x - \sqrt{3} = 0eitherx−3=0</p><p></p><p>x = \sqrt{3}x=3</p><p></p><p>or \: \:x - 2 = 0orx−2=0</p><p></p><p>x = 2x=2</p><p></p><p>$