Question

(x + 2)^3 = 2x( x^2 - 1) Please solve this question by factorization method​

Answer 1

Step-by-step explanation:

(x+2)^3=2×(x^2-1)

(x^3+3.×^2.2+3.x.2^2+2^3=2x^2-2

x^3+6x^2+12x+8=2x^2+2x-2x-2

x^3+6x^2-2x^2+12x-2x+8+2=2x

x^3+4x^2+10x+10=-2x

x^3+4x^2+8x+10

Answer 2

Answer:

Factorisation method

Factorising is the reverse of expanding brackets, so it is, for example, putting 2x² + x - 3 into the form (2x + 3)(x - 1). This is an important way of solving quadratic equations. The first step of factorising an expression is to 'take out' any common factors which the terms have

Step-by-step explanation:

let's solve

$( {x + 2})^{3} = 2 \times ( {x}^{2} - 1) \\ {x}^{3} + {3}^{2} \times 2 + 3 \times {2}^{2} + {2}^{3} = 2 {x}^{2} - 2 \\ {x}^{3} + {6x}^{2} + 12x + 8 = 2 {x}^{2} + 2x - 2x - 2 \\ {x}^{3} + {6x}^{2} - 2 {x}^{2} + 12x - 2x + 8 + 2 = 2x \\ {x}^{3} + 4 {x}^{2} + 10x + 10 = - 2x \\ {x}^{3} + 4 {x}^{2} + 8x + 10$

here's your answer