Question

(x-2)^3=2x(x^2-1) so find it is in the quaradic form or not

Answer 1

(x-2)^3 = 2x(x^2-1) x^3-3*x*2^2+3*x*2^2-2^3=2x^3-2x x^3-12x^2+6x^2-8-2x^3+2x=0 -x^3-6x^2+2x-8=0 Degree of the equation is 3 Therefore Given equation is not quadratic equation