x^2-3✓5x+10=0 find the roots of the given equation
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By using qudratic formula,
x=-b±squareroot of b2-4ac/2a
x=3root5±squareroot of (3 root 5)2 -4(1)(10)/2
x=3root5± squareroot of 45-40/2
x=3root5 ± squareroot of 5/2
x=3root5+root5/2 (or) 3root5-root5/2
x=4root5/2 (or) 2root5/2
x=2root5 (or) root5
hope u got it ...
x=-b±squareroot of b2-4ac/2a
x=3root5±squareroot of (3 root 5)2 -4(1)(10)/2
x=3root5± squareroot of 45-40/2
x=3root5 ± squareroot of 5/2
x=3root5+root5/2 (or) 3root5-root5/2
x=4root5/2 (or) 2root5/2
x=2root5 (or) root5
hope u got it ...
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