X=2/3 & x=-3 are roots of quad eqn ax2+7x+b=0 find the vlue of a and b
Answers
Answered by
2
ツ ¸.•°*”˜ ˜”*°•.¸
║╦╔╗║║╔╗║
╠╣╠╝║║║║║
╩║╚╝╚╚╚╝O
HOPE IT HELPS UHH!!
∧ ∧ ∩
(`・ω・)/
⊂ ノ
(つノ
(ノ
___/(___
/ (___/
 ̄ ̄ ̄ ̄ ̄
║╦╔╗║║╔╗║
╠╣╠╝║║║║║
╩║╚╝╚╚╚╝O
HOPE IT HELPS UHH!!
∧ ∧ ∩
(`・ω・)/
⊂ ノ
(つノ
(ノ
___/(___
/ (___/
 ̄ ̄ ̄ ̄ ̄
Attachments:
Answered by
1
If a & b are the roots of an equation, then then (x-a)(x-b)=0 is a quadratic equation.
x = 2/3, x = -3 are roots, then the equationn will be
---> (x-2/3)(x-(-3))=0
(x-2/3)(x+3) = 0
x^2-(2/3)x+3x-2 = 0
3x^2-2x+9x-6=0
3x^2+7x-6=0 required equation
comparing above equation with general equation
and general equation is ax2+7x+b=0
so that, a=3 & b= -6
Similar questions