Question

x = 2+√3, then x^2+1/x^2​

Answer 1

Answer:

so the answer is 14.

hope it helps you....

Answer 2

Hello,

Given that,    

     $x=2+\sqrt{3}$   -----(i)

                 

Now substitute equation (i) in $x^2 +\frac{1}{x^2}$                                                                            

   We get,    $(2+\sqrt{3} )^2+\frac{1}{(2+\sqrt{3})^2 }$

= $(4+3+4\sqrt{3} ) +\frac{1}{(4+3+4\sqrt{3}) }$                     (∵ $(a+b)^2=a^2+b^2 +2ab$)

= $(7+4\sqrt{3} )+\frac{1}{(7+4\sqrt{3}) }$                                 ( by adding )

= $\frac{(7+4\sqrt{3})^2+1 }{(7+4\sqrt{3}) }$                                              (∵$(a+b)^2=a^2 +b^2+2ab$)

= $\frac{871.96+1}{13.92}$

=$\frac{872.96}{13.92}$

=$62.71$

≈$63$

Hope this helps you!!!

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