Question

(x+2)/3-(x+1)/2=(x-3)/4-2.find the value of x​

Answer 1

Answer:

If x=3−2

2

, find x

4

+

x4

1

?

MEDIUM

ANSWER

x+

x

1

=3−2

2

+

3−2

2

1

x

1

=

3−2

2

1

×

3+2

2

3+2

2

=

1

3+2

2

x+

x

1

=3−2

2

+3+2

2

=6

Squaring on 60th sides.

(x+

x

1

)

2

=36

x

2

+

x

2

1

=36−2⇒x

2

+

x

2

1

=34

Squaring on 60th sides.

(x

2

+

x

2

1

)

2

=(34)

2

x

4

+

x

4

1

=1156−2⇒x

4

+

x

4

1

=1154.

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Answer 2

Answer:

The value of x in (x+2)/3-(x+1)/2= (x-3)/4-2 is 1

Step-by-step explanation:

(x+2)/3 - (x+1)/2= (x-3)/4-2

(x+2)-(x+1)/3-2 =(x-3)/2

(x²+x -2x-2)/3-2=(x-3)/2

(x²-x -2)/1=(x-3)/2

x²-x-2= (x-3)/2

x-2=(x-3)/2

2 ( x-2)=x-3

2x-4= x-3

2x-x = -3+4

x=1