Math, asked by anjalisagunda, 5 months ago

(x+2)/3 -(x+1)/5 = (x-3)/4 -1

Answers

Answered by ad0308
2

Answer:

(x+2)/3-(x+1)/5 = (x-3)/4 -1

[5(x+2)-3(x+1)]/3×5 = [(x-3)-4]/4

(5x+10-3x-3)/15 = (x-3-4)/4

(2x-7)/15 = (x-7)/4

4(2x-7) = 15(x-7)

8x-28 = 15x-105

8x-15x = -105+28

-7x = -77

7x = 77

x = 77/7

x = 11

Answered by abbasali6
0

Answer:

(x+2)/3-(x+1)/5=(x-3)/3

taking (x-3)/3 in left side

x+2)/3-(x+1)/5-(x-3)/3=0

now,taking LCM of 3,5,3 we get=15

now {5(x+2)-3(x+1)-5(x-3)}/15=0

(5x+10-3x-3-5x+15)/15=0

-3x+10-3+15/15=0

-3x+22=15

-3x=15-22

-3x=-7

x=7/3

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