(x + 2)³ + (x - 2)³
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Step-by-step explanation:
We have (x + 2)3 = 2x (x2 - 1)
{tex}\implies{/tex}x3 + 6x2 + 12x + 8 = 2x3 - 2x
{tex}\implies{/tex}x3 - 6x2 - 14x - 8 = 0
it is not of the form ax2 + bx + c = 0, {tex}a \ne 0{/tex}
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