Question

(x^2)^3=x^2^3=x^8 do you agree with the solution​

Answer 1

(x²)³ = x²×x³ =

${x}^{2 \times 3} = {x}^{6}$

You have done wrong. It should be 6 in place of 8 .

While multiplication of the algebric expressions. If you get a condition such that the exponent of the base is having an exponent too. Then , multiply both the exponents. The product such obtained will be your new exponent for the original base.

In the words of identity :

$( {x}^{a} )^{ b } = {x}^{ab}$