(x+2) (30-x-3)=120 by factorisations
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Hi,
(x+2)(30-x-3)=120
(x+2)(27-x)=120
27x - x² + 54 - 2x - 120 = 0
-x² + 25x - 66 = 0
x² - 25x + 66 = 0
66
/\
-22 -3
x² - 22x - 3x + 66 = 0
x( x - 22) - 3( x - 22) = 0
(x - 22)(x - 3) = 0
x - 22 = 0 or x - 3 = 0
x = 22 or x = 3
Hope it helps!!!!!!
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