Question

x^2+34x–408=0 what is the value of x? ​

Answer 1

Step-by-step explanation:

triangle OEB,

OB2 = OE2 + EB2

OB2 = x2 + 52 ---(1)

In triangle OFD,

OD2 = OF2 + FD2

OD2 = (17-x)2 + 122 ---(2)

OB = OD (radius of the given circle)

(1) = (2)

x2 + 52 = (17-x)2 + 122

x2 + 52 = 172 + x2 - 2(17) x + 122

x2 + 25 = 289 + x2 - 34x + 144

x2 - x2 + 34x + 25 - 144 - 289 = 0

34x - 408 = 0

34(x - 12) = 0

x = 12 cm

By applying the value of x in the 1st equation, we get

OB2 = 122 + 52

OB2 = 144 + 25 = 169

OB = √169 = 13 cm

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Answer 2

Answer:

It is a quadratic equation

Step-by-step explanation:

x^2 +34x-408=0

dear please check your question it might be wrong