Math, asked by Joker41, 1 year ago

x^2-3kx+k-3 has one of the zeroes is zero then find k

Answers

Answered by SakshaM725
2
x^2 - 3kx + k - 3 = 0

One zero is 0

Therefore,

x = 0

x^2 - 3kx + k - 3 = 0

0^2 - 3k × 0 + k - 3 = 0

K - 3 = 0

Answer. K = 3
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