X^2+3x+1=0. Find the value of x
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Answered by
0
Answer:
x²+3x+1 = 0
compare the equation with ax²+bx+c = 0
a = 1,b = 3 ,c = 1
b²-4ac
= (3)² -4×1×1
= 9 - 4
= 5
x = -b+-√ b²-4ac /2a
= - 3+-√5/2×1
= -3+-√5/2
x = -3+√5/2 or x = -3-√5/2
Answered by
2
Answer:
x²+3x+1 = 0
compare the equation with ax²+bx+c = 0
a = 1,b = 3 ,c = 1
b²-4ac
= (3)² -4×1×1
= 9 - 4
= 5
x = -b+-√ b²-4ac /2a
= - 3+-√5/2×1
= -3+-√5/2
x = -3+√5/2 or x = -3-√5/2
Explanation:
Hope this answer will help you.
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