Question

x^2 + 3x + 1 = (x-2)^2​

Answer 1

Answer:

x=4

Step-by-step explanation:

${x}^{2} + 3x + 1 = {(x - 2)}^{2}$

${x}^{2} + 3x + 1 = {x}^{2} + {2}^{2} + 2 \times 2 \times x$

${x}^{2} - {x}^{2} + 3x - 4x = 4 - 1$

-1x=3

x=3+1

×=4

Answer 2

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