(x+2)(3x+1)(x-3) find the product.
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Here instead of " -16x"__-19x will come
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(x+3)(3x+1)(x-3)
=3x²+x+9x+3(x-3)
=3x²+10x+3(x-3)
=3x³-9x²+10x²+30x+3x-9
=3x³+x²+33x-9
=3x²+x+9x+3(x-3)
=3x²+10x+3(x-3)
=3x³-9x²+10x²+30x+3x-9
=3x³+x²+33x-9
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