Question

x^2+3x-18=0 by quadratic formula...

Answer 1

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Answer 2

Heya!!! User ✌

Here's your answer friend,

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==> x² + 3x - 18 = 0

Here, On comparing above equation we get,

a = 1, b = 3, c = -18

==> Discriminant (D) = b² - 4ac

==> D = b² - 4ac

==> D = (3)² - 4(1)(-18)

==> D = 9 + 72

==> D = 81

Here, D > 0,

therefore, the given polynomial has two distinct roots.

Therefore, by quadratic formula we have,

==> (-b +- √b² - 4ac)/2a

==> (-3 +- √81 ) / 2(1)

==> (-3 +- 9) /2

==> Therefore,

x = (-3 + 9) /2 or x = (-3 - 9)/2

==> x = 6/2 or x = -12/2

==> x = 3 or x = -6

Are the required zeroes of the given polynomial.

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