Question

x^2-3x+2=0 of alpha and beta are two roots alpha ^2-beta^2​

Answer 1

Answer:

the answer would be 3

Step-by-step explanation:

by factorising the answer, the two zeroes obtained would be 2 and 1.

let 2 be alpha and 1 be beta,

2^2 - 1^2 = 3

hope it helped for a one-marker question

Answer 2

$\Large{\underbrace{\sf{\red{Required\:Solution:}}}}$

⛦ Given :

• x²-3x+2=0

⛦ To find :

•$\alpha {}^{2} - \beta {}^{2} = ?$

⛦ Solution :

As the equation is written in the form

ax² + bx + c = 0

x²-3x+2=0

⟹x²-2x-1x+2=0

⟹x(x-2)-1(x-2)=0

⟹(x-2)•(x-1)=0

⟹x-2=0 or x-1=0

⟹x=2 or x=1

∴2 and 1 are the roots of x²-3x+2 are 2 or 1

let , X= α and β

we have to find:-

⟹α²-β²= (α -β)•(α+ β)

⟹α²-β²= (2 -1)•(2+ 1)

⟹α²-β²= (1)•(3)

⟹α²-β²= 3

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