x^2 - 3x - 2 ≈ 0 ( solve the following using formula 2x^2 + 13x +15 ≈ 0 )
Anonymous:
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Answers
Answered by
12
hay!!
Dear friend -
(I) x²-3x-2=0
=> x²-2x-1x-2
=> x(x-2) +1(x-2)
=> (x+1) (x-2)
(II)
2x²+13x+15=0
=> 2x²+10x+3x+15=0
=> 2x(x+5)+3(x+5)
=> (2x+3) (x+5)
I hope it's help you
Dear friend -
(I) x²-3x-2=0
=> x²-2x-1x-2
=> x(x-2) +1(x-2)
=> (x+1) (x-2)
(II)
2x²+13x+15=0
=> 2x²+10x+3x+15=0
=> 2x(x+5)+3(x+5)
=> (2x+3) (x+5)
I hope it's help you
Answered by
4
hay!!
1.
x²-3x-2=0
x²-2x-1x-2
x(x-2) +1(x-2)
(x+1) (x-2)
2.
2x²+13x+15=0
2x²+10x+3x+15=0
2x(x+5)+3(x+5)
(2x+3) (x+5)
1.
x²-3x-2=0
x²-2x-1x-2
x(x-2) +1(x-2)
(x+1) (x-2)
2.
2x²+13x+15=0
2x²+10x+3x+15=0
2x(x+5)+3(x+5)
(2x+3) (x+5)
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