Physics, asked by dhruvifaldu77, 1 year ago

(x^2+ 3x + 2)^3 + log x^2​

Answers

Answered by sare83
0

Answer:

2㏒x+(x⁶+9x⁵+33x⁴+63x³+66x²+36x+8)

Explanation:

Given that,

(x² + 3x + 2)³ + ㏒x² ↔ (1)

to make our calculation easy

factorise x² + 3x +2

⇒ x² + 3x + 2             (∵the factors of 2 are 1 & 2 to get their sum as 3)

by splitting 3x we get,

⇒ x² + 2x + x +2

⇒ x(x+2) + (x+2)

⇒ (x+2)(x+1)

Now, by substituting this in eq.(1)

⇒ ((x+2)(x+1))³ + ㏒x²

⇒ (x+2)³(x+1)³ + ㏒x²

⇒ (x³ + 2³ + 3x²(2) + 3x(2)²)(x³ + 1³ + 3x²(1) + (3x(1)²) + ㏒x²

(∵(a+b)³ = a³+b³+3a²b+3ab² & ㏒a² = 2㏒a)

⇒(x³+8+6x²+12x)(x³+3x²+3x+1) + 2㏒x

⇒(x⁶+3x⁵+3x⁴+x³+8x³+24x²+24x+8+6x⁵+18x⁴+18x³+6x²+12x⁴+36x³+36x²+12x)+2㏒x

(∵a^m × a^n = a^(m×n) )

⇒(x⁶+9x⁵+33x⁴+63x³+66x²+36x+8) + 2㏒x

HOPE THIS WOULD BE HELPFUL FOR YOU

Answered by Anonymous
0

Answer:

As you didnt mentioned anything i solved integration and differentiation for above question

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