x^2+3x^2+3x+1 p(x-1/2)
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2
x² + 3x² + 3x + 1
=> p(0,2)
Answered by
2
Answer:
Given polynomial is p(x)=x
2
−3x+2
Replace x by 0, we get
p(0)=(0)
2
−3(0)+2
⇒p(0)=0+0+2
⇒p(0)=2
Replace x by 1, we get
p(1)=(1)
2
−3(1)+2
⇒p(1)=1−3+2
⇒p(1)=0
Replace x by 2, we get
p(2)=(2)
2
−3(2)+2
⇒p(2)=4−6+2
⇒p(2)=0
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