Question

x^2-3x^2+6x^2+6x-4 if x=4
$x ^{2} - 3x ^{2} + 6x ^{2} + 6x^{2} - 4 \: if \: x \: is \: 4$

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Answer 1

Answer:

$after \: putting \: value \: \x= 4. \\ = > 1020< - answer.$

Step-by-step explanation:

$x^2-3x^2+6x^2+6x^2-4^2\: \\ if \: \: \: x=4 \\ \: after \: putting \: </p><p>value \: \x = 4. \\ \ = > {4}^{2} - ({3} \times {4})^{2} + ({6} \times {4})^{2} + (6 \times 4)^{2} - 4 \\ = > 16 - 12 {}^{2} + 24 {}^{2} + 24^2 - 4. \\ = > 16 - 144 + 576 + 576 - 4. \\ = > (16 + 576 + 576) - 144 - 4. \\ = > (1168) - 148 = 1020. < - ans.$

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