Question

(x^2-3x+2)(x^3-3x^2)(4-x^2)>=0 solve inequality

Answer 1

Given:

( x² - 3x + 2 )( x³ - 3x² )( 4 - x² ) ≥ 0

( x - 1 )( x - 2 )( x² )( x - 3 )( 4 - x )( 4 + x ) ≥ 0

x ≥ 1 , x ≥ 2 , x ≥ 0 , x ≥ 3, x ≤ - 4 , x ≥ -4

The answers are x ≥ 3 and x ≤ - 4

( -∞, -4][3, ∞)

Hope it helps!