Question

x^2+3x-3600=0 how to solve this quadratic equation?

Answer 1

Step-by-step explanation:

given:x²+3x-3600=0

formula:. -b± √ b²-4ac/2a

here, a=1, b=3, and c= -3600

-3±√3²-4×1×-3600/2×1

-3±√9+14400/2

-3±√14409/2

-3±120/2

x=-3+120/2 and -3-120/2

x= 117/2 and -123/2

hope this helps you