Math, asked by himmu421, 5 months ago

x^2-3x+3y-y^2. plzz help mee

Answers

Answered by chcharishma111

1

Answer:

the question is not fully explained and not proper but i rried some thing and got some thing

Attachments:

Answered by Ktanuj

0

Answer:

1x +1y

Step-by-step explanation:

x^2-3x+3y-y^2

x^2=x×2 =2x

2x-3x= -1x

-1x+3y-y^2

= -1x + 3y - y × 2

= -1x + 3y - 2y

= -1x +1y

please mark me as brainliest

and thank me

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