Question

x^2 +3x - 4 =0
By completing the square method

Answer 1

x^2+3x-4=0

x^2+x-4x-4=0

x(x+1)-4(x+1)=0

(x+1)(x-4)=0 then

x=-1 or x=4

Answer 2

Answer:x=1

Step by-step explanation:

x^2+3x=4

=>(b/2)^2

=>(3/2)^2

=>9/4

add 9/4 on both sides

x^2+3x+9/4=4+9/4

(x+3/2)^2=25/4

x+3/2=√25/4

x=5/4-3/2

x=2/2

x=1

hence proved