Question

x^2-3x+5 mid term factor

Answer 1

$\huge{\orange{\underline{\underline{\bf{\diamond\;Solution:}}}}}$

Given,

Quadratic Equation = x²-3x+5

The Q.E is in the form of 'ax²+bx+c = 0'

Where, a = 1, b = -3, c = 5

By Using Dharacharya Law

$\boxed{\sf{x = \frac{-b±{\sqrt{b²+4ac}}}{2a}}}$

$→\;\Large{\sf{\frac{-(-3)±\sqrt{(-3)²+(4×1×5)}}{2}}}$

$→\;\Large{\sf{\frac{3±\sqrt{9+20}}{2}}}$

$→\;\Large{\sf{\frac{3±\sqrt{29}}{2}}}$

So, Mid Term Factors of the Quadratic Equation are

☞ $\Large\red{\sf{x = \frac{3+\sqrt{29}}{2}}}$

☞ $\Large\green{\sf{x = \frac{3-\sqrt{29}}{2}}}$

Hope It Helps You ✌️