Question

x ^2 +3x -5 = (x +9) ^2​

Answer 1

If we have to find value of x then here we go

Answer 2

${x}^{2} + 3x - 5 = {(x + 9)}^{2}$

Expand

${(x + 9)}^{2}$

using identity ie.,

${(a + b)}^{2} = {a }^{2} + {b}^{2} + 2ab$

So now, it's becomes

${x}^{2} + 81 + 18x$

Now , equate the given (LHS) equation and the newly found equation. So it's becomes

${x}^{2} + 3x - 5 = {x}^{2} + 81 + 18x$

Now, shift all the LHS part to RHS so it become

${x}^{2} + {x}^{2} + 81 + 5 + 18x - 3x = 0$

Now , both the x^2 terms gets cancelled because of opposite sign

$81 + 5 + 18x - 3x = 0$

Now, add and subtract all the like terms

$86 + 15x = 0$

Now, shift 86 to RHS

$15x = - 86$

Now, shift the constant term of x to RHS ie., shift 15 to RHS

$x = - \frac{86}{15}$

Then you can do further division or else stop here so the value of x will in fraction

$x = - 5.733$

HOPE THIS ANSWER HELPS YOU.....