Question

x^2+3x-6 =0 solve by quadratic formula​

Answer 1

$x^2+3x-6=0\\\\a=1\\\\b=3\\\\c=-6\\\\D=b^2-4ac\\\\D=(3)^2-4*1*-6\\\\D=9+24\\\\D=33$

x = (-b ± √D) / 2a

x = (-3 ± √33) / 2

$x =\frac{-3+\sqrt{33}}{2}\\\\or\\\\x=\frac{-3-\sqrt{33}}{2}$