Question

x^2+3x-(a^2+a-2)=0 what the solution of this answer
​

Answer 1

Step-by-step explanation:

We have

x

2

+3x−(a

2

+a−2)=0

⇒x

2

+3x−(a+2)(a−1)=0

⇒x

2

+{(a+2)−(a−1)}x−(a+2)(a−1)=0

⇒{x

2

+(a+2)x}−(a−1)x−(a+2)(a−1)=0

⇒{x+(a+2)}{x−(a−1)}=0

⇒x+(a+2)=0orx−(a−1)=0⇒x=−(a+2)orx=a−1