Question

x^2-3x-k=0 ; d=1 then k=?​

Answer 1

Step-by-step explanation:

Given first derivative d=1

differentiate the equation with respect x then

2x-3=1

2x=4

x=4/2

x=2

then substitute in equation

2^2-3(2)-k=0

4-6-k=0

-2-k=0

k=-2