Math, asked by arpan87, 9 months ago

x^2-3x-m (m+3)÷x^2-3x-1​

Answers

Answered by prasadnandikatla
0

Answer:

x^2-3x-m(m+3)÷x^2-3x-1

x^2 andx^2 are cancelled

-3x and-3x are cancelled

then,

-m(m+3) ÷ -1

-m^2-3m÷-1

=m^2 +3m

=m^2+3

m^2=3

m=√3

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