Question

x^(2)+3xy=28
X^(2)+y^(2)=20
Then X,Y =?

Answer 1

Answer:

x

2

+3xy−28y

2

Consider x

2

+3xy−28y

2

as a polynomial over variable x.

x

2

+3yx−28y

2

Find one factor of the form x

k

+m, where x

k

divides the monomial with the highest power x

2

and m divides the constant factor −28y

2

. One such factor is x+7y. Factor the polynomial by dividing it by this factor.

1. (x−4y)(x+7y)