Question

X^2-√3xy+2y^2=5 at (√3,2) diff.w.r.t.x

Answer 1

Answer:

${x}^{2} - \sqrt{3} xy + 2 {y }^{2} = 5 \\ putting \: x = \sqrt{3} \: and \: y = 2 \: we \: get \\ {( \sqrt{3)} }^{2} - \sqrt{3} \times \sqrt{3} \times 2 + 2 }( {2})^{2} = 3 - 6 + 8 \\ = 5 \\ here \: lhs = 5 \: and \: rhs = 5 \\ hence \: its \: proved \\ \\ thank \: you$