Question

(x-2/3y)^3 please solve this using Identity​

Answer 1

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We know the identity ,

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³= x³ - 2x²y + 4y²/3 - 8y³/27

Answer 2

Step-by-step explanation:

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³

We know the identity ,( a - b )³ = a³ - 3a²b + 3ab² - b³Here ,(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³= x³ - 2x²y + 4y²/3 - 8y³/27