Question

(x/2+3y/4)^2 using identites

Answer 1

(x/2+3y/4)²

Using the identity (a + b)² = a² + b² + 2ab

(x/2)² + (3y/4)² + 2(x/2 × 3y/4)

= x²/4 + 6y²/16 + 2(3xy/8)

= x²/4 + 6y²/16 + 6xy/8

= x²/4 + 3y²/8 + 3xy/4

Kindly Follow !!

Answer 2

Answer:

$( \frac{x}{2} + \frac{3y}{4}) ^{2}$

$(a + b)^{2} = {a}^{2} + 2ab + {b}^{2}$

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