Question

X^2+3y=5 and x^2+xy+2y^2=4 simultaneously

Answer 1

ANSWER

Let's solve for x.

x2+3y=5

Step 1: Add -3y to both sides.

x2+3y+−3y=5+−3y

x2=−3y+5

Step 2: Take square root.

x=√−3y+5 or x=−√−3y+5

SORRY AGAIN ONE I DONT KNOW