Question

(x^2) -4/2=6
answer this please​

Answer 1

$\large\sf\underline{Given\::}$

• $\sf\:x^{2}-\frac{4}{2}=6$

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$\large\sf\underline{To\:find\::}$

• Value of x

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$\large\sf\underline{Solution\::}$

$\sf\:x^{2}-\frac{4}{2}=6$

• Finding LCM of 2 and 1 in LHS

$\sf\implies\:\frac{2x^{2}-4}{2}=6$

• Transposing 2 to the other side

$\sf\implies\:2x^{2}-4=6 \times 2$

$\sf\implies\:2x^{2}-4=12$

• Transposing 4 to the other side

$\sf\implies\:2x^{2}=12+4$

$\sf\implies\:2x^{2}=16$

• Transposing 2 to the other side

$\sf\implies\:x^{2}=\cancel{\frac{16}{2}}$

$\sf\implies\:x^{2}=8$

• Transposing square to the other side

$\sf\implies\:x=\sqrt{8}$

$\large{\mathfrak\red{\implies\:x\:=\:2\sqrt{2}}}$

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$\large\sf\underline{Verifying\::}$

$\sf\:x^{2}-\frac{4}{2}=6$

• Substituting the value of x as $\sf\:2\sqrt{2}$

$\sf\implies\:(2\sqrt{2})^{2}-\frac{4}{2}=6$

$\sf\implies\:(4 \times 2 )-\frac{4}{2}=6$

$\sf\implies\:8-\frac{4}{2}=6$

• LCM of 1 and 2 in LHS

$\sf\implies\:\frac{16-4}{2}=6$

$\sf\implies\:\cancel{\frac{12}{2}}=6$

$\sf\implies\:6=6$

$\small\fbox\blue{Hence\:Verified}$

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$\dag\:\underline{\sf So\:the\:required\:value\:is\:2\sqrt{2}}$

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!! Hope it helps !!