x^2/4+2x-5.................
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Explanation:
Correction : Polynomial is x²/4 + 2x - 5
Let Polynomial be f(x) = x²/4 + 2x - 5
Step : I { Solve Polynomial }
f(x) = x²/4 + 2x - 5
= x² + 8x - 20 = 0 ×4
= x² + 8x - 20
Step : 2 { Solve Quadratic Polynomial }
☞x² + 8x - 20 = 0
☞x² + 10x - 2x - 20 = 0
☞x(x+10)-2(x+10) = 0
☞(x-2)(x+10) = 0
So, Values of x are 2 & and -10 .
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