Question

x^2/4+2x-5.................

Answer 1

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Answer 2

Explanation:

Correction : Polynomial is x²/4 + 2x - 5

Let Polynomial be f(x) = x²/4 + 2x - 5

Step : I { Solve Polynomial }

f(x) = x²/4 + 2x - 5

= x² + 8x - 20 = 0 ×4

= x² + 8x - 20

Step : 2 { Solve Quadratic Polynomial }

☞x² + 8x - 20 = 0

☞x² + 10x - 2x - 20 = 0

☞x(x+10)-2(x+10) = 0

☞(x-2)(x+10) = 0

So, Values of x are 2 & and -10 .